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What is the approximate volume of a cone with a height of 6 mm and radius of 18 mm? Use 3.14 to approximate pi, and express your final answer to the nearest tenth.
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@Michele_Laino i got 2034.7 mm3 could u make sure im correct
you have to apply the same formula as before for previous exercise, namely: \[\Large V = \frac{{\pi \times {R^2} \times H}}{3}\] where R is the radius, and H is the height of the cone respectively
i did
so we get: \[\Large V = \frac{{\pi \times {R^2} \times H}}{3} = \frac{{3.14 \times {{18}^2} \times 6}}{3} = ...?\]
I got: V=2034.72 mm^3
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So your answer is correct!
thanks
thanks!
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