Question

A boat leaves Port A and travels due east. Port B is 15 mi due north of Port A, and Port C is 24 mi due south of Port A. The boat is 25 mi from Port C.

How far is the boat from Port B? Round to the nearest tenth of a mile.
____mi

Answer 1

@leon549

Answer 2

@leon549

Answer 3

well you need to do pythagoras' theorem twice


use the triangle ACboat to find x....

it will be \[x^2 = 25^2 - 24^2\]

then in the upper triangle you have 2 shorter sides

to find the distance of B to the boat

Answer 4

7

Answer 5

is it 17 or 16?

Answer 6

well the upper triangle is



\[y^2 = 15^2 + 7^2 \]