Find all solutions on the interval [0,2pi)
Sin(2x)=-sqrt3/2

I got 2pi/3 and 5pi/6, can someone check this for me?
Will FAN and MEDAL

Question

Find all solutions on the interval [0,2pi)
Sin(2x)=-sqrt3/2

I got 2pi/3 and 5pi/6, can someone check this for me?
Will FAN and MEDAL

anonymous · Answer

You missed 2 solutions

anonymous · Answer

The x is multiplied by 2, so if the interval for x is 0 ≤ x < 2π, then the interval for 2x is 0 ≤ 2x < 4π

anonymous · Answer

So what I have to add two more angles

anonymous · Answer

@peachpi

anonymous · Answer

yes. you already have 2x = 4π/3 and 5π/3. Add 2π to those to get the other values for 2x. Then x = 5π/3 and 11π/6

anonymous · Answer

@minisweet4

anonymous · Answer

ow do I add 2pi to an angle like how do I know what number to go to ? @peachpi

anonymous · Answer

Get a common denominator
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