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In triangle ABC, a = 8, b = 6, and C = 60°. Find the measure of A. 16° 46° 74° 106°
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@jim_thompson5910 can you help me please
|dw:1432428147795:dw|
step 1) use the law of cosines to find the length value of c step 2) use law of sines to find angle A
what would i put for SIN A, SIN B, and SIN C for step 1 @jim_thompson5910
c^2 = a^2 + b^2 - 2*a*b*cos(C) c^2 = 8^2 + 6^2 - 2*8*6*cos(60) c^2 = 8^2 + 6^2 - 2*8*6*0.5 ... ... ... c = ???
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52?
@jim_thompson5910
c^2 = 52 so c itself is ???
7.21?? @jim_thompson5910
we'll leave it as \[\Large \sqrt{52}\] |dw:1432429030834:dw|
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