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Indices and Logarithms @rational
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Given that \[\log_m5=0.5~andlog_m7=0.8,find~the~value~of\] \[a)\log_m9.8\]
gimmick is to write \(9.8\) in terms of \(5\) and\(7\) only
\[9.8=\frac{98}{10}=\frac{49}{5} = \frac{7^2}{5}\]
that'll do it
\[=\log_m7^2\div~\log_m5\]
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\[=2(0.8)-0.5\]
careful, \[\log \left(\frac{a}{b}\right) \ne \frac{\log (a)}{\log (b)}\]
that's for sure !
\[=1.6-0.5\]\[=1.1\] Thnx @rational @satellite73 :)
yw
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