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Mathematics 13 Online
Parth (parthkohli):

LET'S BEGIN.

Parth (parthkohli):

\[\sum_{n= 1}^{\infty}\dfrac{\tan(\theta/2^n)}{\cos(\theta/2^{n-1})}\]

Parth (parthkohli):

@dan815

OpenStudy (dan815):

okay :)

OpenStudy (anonymous):

Is it theta/(2^(n-1)) or (theta/2)^(n-1)?

OpenStudy (dan815):

|dw:1432449799486:dw|

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