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How many terms are in this series: 1 – 2 + 4 – 8 + . . . – 131072
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-0
this is a geomeric series
geometric*
if you divide two consecutive terms, you get a ratio of -2
$$\Large (-2)^0 + (-2)^1 + (-2)^2 + (-2)^3+ ... (-2)^{n-1} $$
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an=a1(r)^n-1
so you need to solve (-2)^(n-1) = – 131072
you can also solve this using logarithms
n=18
Determine the sum: 25 + 5 + 1 + ...
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the ratio is 1/5
$$\Large \sum_{n=0}^{\infty} ar^{n-1}= \frac{a}{1-r}~,~ |r| < 1 $$
a1=25
right
25/1/5
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be careful
$$\Large \sum_{n=0}^{\infty} ar^{n-1}= \frac{a}{1-r}~,~ |r| < 1 \\~\\\Large \sum_{n=0}^{\infty} 25\cdot (1/5)^{n-1}= \frac{25}{1-1/5}~,~ |1/5| < 1 ~\checkmark \\~\\ \Large \frac{25}{4/5} = 25 \cdot \frac 5 4 $$
31.25!
i almost forgot to do 1-1/5
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