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What is the value of the expression 8–^2?
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is it \(\huge 8^{-2}\)
yes
here we apply the law of indices \(\Large\color{red}{a^{-n}=\frac{1}{a^n}}\)
?
@LegendarySadist
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It's saying \[8^{-2}=\frac{ 1 }{ 8^{2} }\]
is it 1 _ 16
\[\frac{ 1 }{16? }\]
\[8^{2}=8*8\]
\[\frac{ 1 }{64 }\]
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correct :)
Yes, that would be it.
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