Question

help

Answer 1

@irishboy123

Answer 2

the idealised MA should be 4 because you are pushing 1m from the fulcrum with say force F, and the load is pushing back with say load L at 0.25m from fulcrum. so, in ideal world F * 1 = W * 0.25, so W/F = 1/ 0.25 = 4 idealised.

but from the graph, it looks like the actual MA is given by 160/50 = 16/5 compared to idealised 16/4.

spelling this out further, from the graph it take 50N effort to lift 160 whereas it should only take 40N.

in terms of efficiency, as it takes 50N to lift 160N, the ratio of work output to work input would be (160 * 0.25) / (50 * 1) = 80%. in an ideal machine that would be (160 * 0.25) / (40 * 1) = 100%

Answer 3

Thanks so much! You helped me a lot!