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The position of an object at time t is given by s(t) = -1 - 13t. Find the instantaneous velocity at t = 8 by finding the derivative. Any help would be appreciated. :)
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HI!!
HI!
if \(s\) is the position, and it is a line \(s(t)=1-13t\) then the velocity is the slope, which is evidently \(-13\)
How did you get that?
the slope?
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just like \(y=mx+b\) the slope is \(m\)
you have \[-13t+1\] the slope is \(-13\)
Oh, it was that simple.. thanks XD
But what if t=8?
slope of a line does not depend on the number for \(t\) it is a constant in this case \(-13\)
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they just threw that in there to confuse you i guess
ok thank you
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