OpenStudy (anonymous):

The position of an object at time t is given by s(t) = -1 - 13t. Find the instantaneous velocity at t = 8 by finding the derivative. Any help would be appreciated. :)

2 years ago
OpenStudy (misty1212):

HI!!

2 years ago
OpenStudy (anonymous):

HI!

2 years ago
OpenStudy (misty1212):

if \(s\) is the position, and it is a line \(s(t)=1-13t\) then the velocity is the slope, which is evidently \(-13\)

2 years ago
OpenStudy (anonymous):

How did you get that?

2 years ago
OpenStudy (misty1212):

the slope?

2 years ago
OpenStudy (misty1212):

just like \(y=mx+b\) the slope is \(m\)

2 years ago
OpenStudy (misty1212):

you have \[-13t+1\] the slope is \(-13\)

2 years ago
OpenStudy (anonymous):

Oh, it was that simple.. thanks XD

2 years ago
OpenStudy (anonymous):

But what if t=8?

2 years ago
OpenStudy (misty1212):

slope of a line does not depend on the number for \(t\) it is a constant in this case \(-13\)

2 years ago
OpenStudy (misty1212):

they just threw that in there to confuse you i guess

2 years ago
OpenStudy (anonymous):

ok thank you

2 years ago