Question

The circle below is centered at the point (-2, 1), and has a radius of length 3. What is its equation?

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Answer 1

equation for a circle center (0,0) x^2 + y^2 = r^2
circle with center (h,k) (x-h)^2 + k = 0

Answer 2

So it would be -2^2+1^2=3^2 ?

Answer 3

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Answer 4

need to verify what I had
(x--2)^2 + (y-1)^2 = 3^2
(x + 2)^2 + (y-1)^2 = 3^2

Answer 5

option D

Answer 6

(x + 2)^2 + (y - 1)^2 = 9

Answer 7

Aight thanks for the help!

Answer 8

sorry it took so long
welcome