Question

One number is equal to the square of another. Find the numbers if both are positive and their sum is 272.

Answer 1

HI!!

Answer 2

call one number \(x\) and the other \(y\) then \(y=x^2\)

Answer 3

solve
\[x^2+x=272\]

Answer 4

I understand that x=16 but what is the other number?

Answer 5

It can't be 17 even though it equals 272

Answer 6

136 is the answer

Answer 7

if one number is 16 then the other is \(16^2\)

Answer 8

or if you prefer
\[272-16\]

Answer 9

16 and 256 was the answer