PLEASE HELP ME!!!! From a boat on the lake, the angle of elevation to the top of a cliff is 15°54'. If the base of the cliff is 967 feet from the boat, how high is the cliff (to the nearest foot)?
ill try
this time fan me though lol
nvm i dont get it
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do u hve any formulas??
Just any that go with pre-cal
damm pre-cal give me a min
okay thank you!!
np...hve u tried drawing a diagram??
No I really don't know how to do it
ok i got u
first draw triangle between tha boat, tha top of tha cliff, and tha bottom of tha cliff
the horizontal distance from tha boat to tha base of tha cliff is 967ft
Okay, I've got everything drawn out but I don't know how to solve it
yea thass tha problem im having
From what I've tried, would the answer be 275.46?
in feet?
i would think so
but just to be sure try multiplying the ft by the angle
u got it??
I honestly have no idea..I think it's right.. did you figure it out?
not yet..i cant do this in my head let me get my calculator
arctan (sin (pi/2)) sin (pi/2) = 1 arctan 1 = pi/4 cliff's height H is the side of a right triangle having opposite angle 15°54' and the other side 967ft H = 967 tan(15°54') = 275ft Is this correct?
i really dont think my answer is right....275.46 and hope its right
hahaha thanks
ur welcome...sorry i couldnt hlp more but im not really familiar with pre-cal
It's all good at least you tried! Have a good one! (:
u too and if u need hlp with anything else jus let me kno:)
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