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If y varies inversely as the square of x, and y=7/4 when x=1, find y when x=3 a. y=1/3x^2; y(3)=1/27 b. y=4/7x^2; y(3)=4/63 c. y=7/4x^2; y(3)=7/36 @Nnesha
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what's the equation for inverse variation ? remember now it's x^2
The equation is... y=k 1/x?
yes right but now it should be x^2 |dw:1432618509310:dw| same like other one first find k and then y value :-)
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