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OpenStudy (ohohaye):
A complex number will, in general, have ____ sixth complex roots
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OpenStudy (agl202):
The nth (6th) roots of a complex number will lie on a circle with radius and will be at an angle of 2 pi/n (2 pi/6) from each other
OpenStudy (ohohaye):
Wait so it would be (2π/6)?
OpenStudy (ohohaye):
@Agl202
OpenStudy (agl202):
No, hint: look at the fundamental theorem of algebra. It would be 6 sixth complex roots...
OpenStudy (ohohaye):
So 6?
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OpenStudy (ohohaye):
@Agl202
OpenStudy (agl202):
Yes! U got it!
OpenStudy (ohohaye):
Thank you!!!
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