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Mathematics 14 Online
OpenStudy (anonymous):

please help me :)

OpenStudy (anonymous):

http://gyazo.com/eceb0f38a0cb88c56abd9f2d7849d45f question in link:)

OpenStudy (triciaal):

summary left or right changes the x value left is negative and right is positive up or down changes the y value up is positive and down is negative

OpenStudy (triciaal):

in the diagram from blue to red moved 3 places left and 4 units up (x, y) goes to (x-3, y +4)

OpenStudy (anonymous):

i tried to put h(x)=-3+4 but it wasnt the answer

OpenStudy (anonymous):

soo what would it be then

OpenStudy (anonymous):

So yoy have h(x)= ax2+bx+c C is where the graph cross the y C=-5 Now when x=-5, y=0 So 0=ax2+bx-5 25a-5b=5 and you can see that when x=-1, y=0 So 0=ax2+bx-5 a-b=5 a-b=5 (*-5) 25a-5b=5 ----------- -5a+5b=-25 25a-5b=5 ------------ 20a=-20 A=-1 So A-b=5 -1-b=5 B=-4 So H(x)=-x2-4x-5

OpenStudy (triciaal):

(x+3)^2 -9 + 4 = 0

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