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Algebra
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An arrow is shot vertically upward from a platform 39 ft high at a rate of 167 ft per sec. When will the arrow hit the ground? Use the formula: h = −16t2 + v0t + h0. (Round your answer to the nearest tenth.)
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Do you have answer choice or no?
No I don't. I got 10.7 for an answer but I don't know if that is correct or not
Okay, hold on
This is what I got h=−16t2+t+1
Idk
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h=-16t^2+167t+39 is the equation. I am supposed to use the quadratic formula to solve it when h=0
When I did the formula i got some weird negative number and 10.66something so 10.7
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