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Help! Simplify: (sin Θ − cos Θ)^2 − (sin Θ - cos Θ)^2
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sin2Θ
how'd you get that though...
sin^2 -2sin cos + cos^2 -(sin^2 -2sin Cos + cos^2) sin^2 -2sincos + cos^2 -sin^2 +2sinCos -cos^2
2*sin(Θ)*cos(Θ) = sin(2Θ) sin(Θ)*cos(Θ) = (1/2)*sin(2Θ)
you don't have to distribute but good to do it for practice both parentheses are same so let's say (sin Θ − cos Θ)^2 = x^2 so \[\huge\rm x^2 -x^2 = ?\]
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so the answer would be zero?
yes right
okay, thank you guys!!!
np
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