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Mathematics 13 Online
OpenStudy (anonymous):

(143(5) + 67)5 ___________ A.1950 B.1955 C.1956 D.1953

OpenStudy (welshfella):

the way you have written the problem gives an answer of 3910

OpenStudy (welshfella):

have you got the parentheses in the right place?

OpenStudy (welshfella):

by the order of operations you work out the 143* 5 first then add the 67. Then multiply this result by 5.

OpenStudy (welshfella):

PEDMAS ParenthesesExponentialsDivideMultiplyAddSubtract

OpenStudy (welshfella):

an if there are parentheses within parentheses you work out the inner ones first.

OpenStudy (anonymous):

ohh thanks

OpenStudy (welshfella):

3910 = 2*1955 so might there be a division by 2 somewhere?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

i just asked my teacher

OpenStudy (anonymous):

first multiply 143*5. Add 67. Multiply that no. by 5

OpenStudy (anonymous):

thanks for the help @as12 and @welshfella

OpenStudy (welshfella):

yw

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