Question

Evaluate. cube root of 7 multiplied by the square root of 7 over sixth root of 7 to the power of 5

Answer 1

\[\frac{ \sqrt[3]{7} \times \sqrt{7}} { \sqrt[6]{7}^{5} }\]

cube root 7 = 7^1/3
sqrt 7 = 7^1/2

(5sixth root 7 ) = 7 ^5/6

use addition and subtraction of indices to simplify

Answer 2

correction: ^^

(sixth root 7)^5 = 7^5/6