Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (pink.1d):

Which logarithmic graph can be used to approximate the value of y in the equation 2^y = 3?

OpenStudy (pink.1d):

OpenStudy (pink.1d):

@Vocaloid @malice

OpenStudy (pink.1d):

@hero @dan815 @Preetha @Michele_Laino @Abhisar

OpenStudy (pink.1d):

@mathstudent55

OpenStudy (anonymous):

@Jaynator495 @nechirwan

OpenStudy (anonymous):

sorry lol I suck at math

OpenStudy (anonymous):

Mann..... I do not recall this prob at all :.:

OpenStudy (anonymous):

@MrNood @mathmate Can one of you guys help?

OpenStudy (pink.1d):

PLEASE I WILL FAN MEDAL AND ALL THAT

OpenStudy (anonymous):

So sorry, I have been really busy today..... brb ttyl!!

OpenStudy (pink.1d):

I SEE SOMEONE kkkkk byeee

OpenStudy (pink.1d):

@MrNood can u help me?

OpenStudy (anonymous):

byeeeeee

OpenStudy (pink.1d):

great he left 2:((((

OpenStudy (pink.1d):

@gibbs @bvb.baby9

OpenStudy (gibbs):

i cant see it

OpenStudy (pink.1d):

its the first thing i attached

OpenStudy (pink.1d):

@bvb.baby9 can you see it?

OpenStudy (anonymous):

my computer wont let me see the graph sorry hope you get help

OpenStudy (pink.1d):

thanks

OpenStudy (pink.1d):

@Vocaloid

OpenStudy (pink.1d):

@Vocaloid i need your help right now

OpenStudy (gibbs):

i cant see the picture i ment

OpenStudy (pink.1d):

@Vocaloid wait please dontt tell me u cant see it either

Vocaloid (vocaloid):

Hm, it's been a while since I've done this type of problem, gimme a second

OpenStudy (pink.1d):

@gibbs ?

OpenStudy (pink.1d):

picture?

OpenStudy (pink.1d):

ok

OpenStudy (pink.1d):

bx=y then it can be converted to logb(y)=x

OpenStudy (pink.1d):

\[\log _{2}\] 3

Vocaloid (vocaloid):

alright, we have the equation 2^y = x, and we can convert that to (y) = log2(x) = log(x)/log(2) which matches with the third graph

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!