Question

What is the equation of the line, in standard form, that passes through (4, -3) and is parallel to the line whose equation is 4x + y - 2 = 0?

4x - y = 13
4x + y = 13
4x + y = -13

Answer 1

HI!!

Answer 2

HI? can u help?

Answer 3

you answer has to have \(4x+y\) in it right?

Answer 4

not \(4x-y\) so you can forget the first one

Answer 5

idek

Answer 6

the line you are given in the question is
\[\huge 4x+y-2=0\] which has \(4x+y\) in it

Answer 7

okay

Answer 8

and you want it to pass through \((4,-3)\) right?

Answer 9

Yes.

Answer 10

the \(4\) is the \(x\) and the \(-3\) is the \(y\) so lets substitute \(4\) for \(x\) and \(-3\) for \(y\) in \[4x+y\] and see what we get

Answer 11

I got 11=0

Answer 12

i.e. compute
\[4\times 4+(-3)\]

Answer 13

\(11=0\)??!!

Answer 14

I'm literally confused.

Answer 15

what is
\[\huge 4\times 4-3\]?

Answer 16

13

Answer 17

yeah if you think \(11=0\) you must be confuffled

Answer 18

right \(13\)

Answer 19

so it must be
\[4x+y=13\]

Answer 20

TYSM!!!!!

Answer 21

parallel lines have the same slope
4 x + y - 2 = 0 slope is -4
passing through (4, -3)
y --3 = -4(x - 4)
y + 3 = -4x + 16
standard form
4 x + y = 13