Mathematics
14 Online
OpenStudy (anonymous):
WILL MEDAL! What is the sum of the series?
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OpenStudy (anonymous):
\[\sum_{n-1}^{20} (5-n)\]
OpenStudy (perl):
Is this the series?
$$\Large{ \sum_{n=1}^{20} (5-n)}$$
OpenStudy (anonymous):
Yes I didn't mean to put the minus sign.
OpenStudy (amilapsn):
Have you learned arithmatic series?
OpenStudy (perl):
$$\Large{
\sum_{n=1}^{20} (5-n)
\\\sum_{n=1}^{20} 5-\sum_{n=1}^{20} n
}$$
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OpenStudy (anonymous):
Yeah I just forgot.
OpenStudy (amilapsn):
Do you know the formula \[S_n=\frac{n}{2}\{2a+(n-1)d\}\]
OpenStudy (anonymous):
I don't remember it.
OpenStudy (amilapsn):
Ok.... That doesn't matter...
OpenStudy (amilapsn):
As perl mentioned, \(\sum_{n=1}^{20}5-n=\sum_{n=1}^{20}5-\sum_{n=1}^{20}n\) ok?
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OpenStudy (anonymous):
Yes
OpenStudy (amilapsn):
Then what do you think about \[\sum_{n=1}^{20}5\]?
OpenStudy (anonymous):
How do I figure it out?
OpenStudy (amilapsn):
\[\sum_{n=1}^{20}5=5+5+5+\ldots+5(20\ times)\] ok?
OpenStudy (anonymous):
So 100?
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OpenStudy (amilapsn):
Bingo!
OpenStudy (amilapsn):
Then what about \(\sum_{n=1}^{20}n\)?
OpenStudy (anonymous):
20?
OpenStudy (amilapsn):
No No....
OpenStudy (amilapsn):
Just extend it like I did for \[\sum_{n=1}^{20}5\]
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OpenStudy (anonymous):
20n?
OpenStudy (amilapsn):
Like this:
\[\sum_{n=1}^{20}n=1+2+3+\ldots+19+20\]
ok?
OpenStudy (anonymous):
Ohhh
OpenStudy (anonymous):
210
OpenStudy (anonymous):
Then 100-210 right?
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OpenStudy (anonymous):
-110
OpenStudy (amilapsn):
yes!!
OpenStudy (anonymous):
Thank you so much for your help and not just giving me the answer!!
OpenStudy (amilapsn):
You're welcome. Cheers!!