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I dont understand this Using the discriminant how many real number solutions does this equation have 3x^2-2=5x
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ax2+bx+c=0 discriminate=b*b-4ac find it
what is value
So I would set it up how
a=3,b=-5,c=-2 so D=-5*-5-4*3*-2=25+24=49 taking sqrt give 7 and -7 so two real solution because 7 and -7
3x^2-5x-2=0 compare with ax^2+bx+c=0 give value of a,b,c.
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So you solve it normally and take the square root
3 -5 2
since D*D=b*b-4*a*c if this value is -ve then U can not find sqrt of D then no real solution .
it give no. of solution not solution of x.
Oh ok that makes some sense thank you for helping me
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