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3 {2/3} x {-2 {1/4} }
3 + 2[4x – (4 + 3x)] = –1 3 + 2[4x – 1(4 + 3x)] = –1 3 + 2[4x – 1(4) – 1(3x)] = –1 3 + 2[4x – 4 – 3x] = –1 3 + 2[1x – 4] = –1 3 + 2[1x] + 2[–4] = –1 3 + 2x – 8 = –1 2x + 3 – 8 = –1 2x – 5 = –1 2x – 5 + 5 = –1 + 5 2x = 4 x = 2
It has to be in fraction or would that be 1 [1/1]
yes
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