Question

Factor: x2 + 11x + 28
A. (x + 7)(x + 4)
B. (x + 7)(x - 4)
C. (x + 8)(x + 3)
D. (x + 14)(x + 2)

Answer 1

@Aureyliant

Answer 2

Sure.. give me two mins

Answer 3

okay :) @Aureyliant

Answer 4

Okay, so first off, I need to know your understanding of factoring trinomials before I give you the straight out answer. (I give explanations too but I just need to know you understand this, too)

Answer 5

okay i didnt get it that much @Aureyliant

Answer 6

Trying to factor by splitting the middle term

2.1 Factoring x2+11x+28

The first term is, x2 its coefficient is 1 .
The middle term is, +11x its coefficient is 11 .
The last term, "the constant", is +28

Step-1 : Multiply the coefficient of the first term by the constant 1 • 28 = 28

Step-2 : Find two factors of 28 whose sum equals the coefficient of the middle term, which is 11 .

-28 + -1 = -29
-14 + -2 = -16
-7 + -4 = -11
-4 + -7 = -11
-2 + -14 = -16
-1 + -28 = -29
1 + 28 = 29
2 + 14 = 16
4 + 7 = 11 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 4 and 7
x2 + 4x + 7x + 28

Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x+4)
Add up the last 2 terms, pulling out common factors :
7 • (x+4)
Step-5 : Add up the four terms of step 4 :
(x+7) • (x+4)
Which is the desired factorization

Final result :

(x + 7) • (x + 4)

Answer 7

Read this and ask me any Q's or tell me anywhere you're confused.

Answer 8

wait did you mean 2x or x+2

Answer 9

x2 is aka x^2

Answer 10

i get it now @Aureyliant

Answer 11

AWESOME!! I love "hearing" that from people I help.

Answer 12

Need anymore help? Just tag me :)