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Mathematics 15 Online
OpenStudy (anonymous):

I NEED MATH HELP BAD MEDALS WILL BE GIVEN

OpenStudy (anonymous):

On what?

OpenStudy (anonymous):

can someone help me please

OpenStudy (anonymous):

one sec

OpenStudy (anonymous):

I will help

OpenStudy (anonymous):

A catault launches a boulder with an upward velocity of 120ft/s. The height of the boulder H in feet after t secondds is given by the function h=-16^2+120t+10 How long does it take to reach maximum height? what is the boulders maximum height round to the nearest hundredth if necessary

OpenStudy (anonymous):

catapult sorry for the miss type

OpenStudy (anonymous):

will u give me a medal??

OpenStudy (anonymous):

The first derivative of H e is v V=-32t+120 At maximum height v=0 -32t+120=0 32t=120 T= 3.75 sec So substitute t on h fuction H=-16x3.75^2+120x3.75+10 H=-225+360+10 H=145 meters

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