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A catault launches a boulder with an upward velocity of 120ft/s. The height of the boulder H in feet after t secondds is given by the function h=-16^2+120t+10 How long does it take to reach maximum height? what is the boulders maximum height round to the nearest hundredth if necessary
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catapult sorry for the miss type
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The first derivative of H e is v V=-32t+120 At maximum height v=0 -32t+120=0 32t=120 T= 3.75 sec So substitute t on h fuction H=-16x3.75^2+120x3.75+10 H=-225+360+10 H=145 meters
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