Question

What are the solutions to the system? (Hint: graphing is the easiest!)
y = x2 + 2x – 45
y = -3x + 5

Answer 1

would it be y=x(x+2)-45 -x^2-2x+y+45=0

Answer 2

plug y=-3x+5 in the other eq. and find x

Answer 3

Y=x2+2x-45
Y=0-3x+5 (multiply by -1)
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Y=x2+2x-45
-Y=0+3x-5
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0=x2+5x-50

Use baskara
Delta=225
X1=5
X2=-10
Substitute these values on one equation
Y=-3x+5
Y=-10
Y=35
So (5,-10) and (-10,35)

Answer 4

\[x^2+2x-45=-3x+5\]
\[x^2+2x+3x-45-5=0\]
\[x^2+5x-45=0\] find x
either by making factors or using quadratic formula

Answer 5

correction
write -50 in place of -45

Answer 6

thank you both very much I don't know who I should medal but I will fan you both

Answer 7

np