What are the solutions to the system? (Hint: graphing is the easiest!)
y = x2 + 2x – 45
y = -3x + 5

Question

What are the solutions to the system?  (Hint: graphing is the easiest!)
	y = x2 + 2x – 45      			
y = -3x + 5

anonymous · Answer

would it be y=x(x+2)-45 -x^2-2x+y+45=0

anonymous · Answer

plug y=-3x+5 in the other eq. and find x

anonymous · Answer

Y=x2+2x-45
Y=0-3x+5 (multiply by -1)
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Y=x2+2x-45
-Y=0+3x-5 
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0=x2+5x-50

Use baskara
Delta=225
X1=5
X2=-10
Substitute these values on one equation 
Y=-3x+5
Y=-10
Y=35
So (5,-10) and (-10,35)

anonymous · Answer

$$x^2+2x-45=-3x+5$$
$$x^2+2x+3x-45-5=0$$
$$x^2+5x-45=0$$ find x
either by making factors or using quadratic formula

anonymous · Answer

correction 
write -50 in place of -45

anonymous · Answer

thank you both very much I don't know who I should medal but I will fan you both

anonymous · Answer

np