According to Carnot, what does the efficiency of a heat engine depend on?
A. the input temperature only
B. the exhaust temperature only
C. the ratio of input temperature to exhaust temperature
D. the ratio of exhaust temperature to input temperature
***not sure! thanks:)
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OpenStudy (michele_laino):
as I wrote before, the efficiency of a machine of Carnot, is:
\[\Large \eta = 1 - \frac{{{T_2}}}{{{T_1}}}\]
where T_1 is the temperature of the hot reservoir
T_2 is the temperature of the cold reservoir
OpenStudy (anonymous):
ohh okay!! so it depends on exhaust energy, right? choice B?
OpenStudy (michele_laino):
no, since we have two temperatures
OpenStudy (anonymous):
ohh okay! sorry!! so it should be choice C?
OpenStudy (michele_laino):
hint:
this quantity:
\[\Large \frac{{{T_2}}}{{{T_1}}}\]
is a ratio
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