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Using the quadratic formula to solve 5x = 6x2 – 3, what are the values of x?
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6x^2-5x-3=0 Right?
U know a stanrd quadrutic equation is ax^2+bx+c=0
Solution x=(-b+-root(b^2-4ca))/2a
In ur given equation a=6 b=-5 c=-3
x=?
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5x=6x^2-3 --> 5x-5x=6x^2-5x-3 6x^2-5x-3 formula--> x= [-b +-( sqrt b^2-4ac)]/2a a=6 b= -5 c= -3 x= 5+- [sqrt(-5^2-4(6)(-3)/2(6) 5+-sqrt(25+72)/12 5+-sqrt(97/12)
U should not give the whole solution in 1 post @hockeychick23
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