Question

The work of a student to solve a set of equations is shown:

Equation 1: m = 8 + 2n
Equation 2: 4m = 4 + 4n

Step 1: –4(m) = –4(8 + 2n) [Equation 1 is multiplied by –4.]
4m = 4 + 4n [Equation 2]
Step 2: –4m = –32 – 8n [Equation 1 in Step 1 is simplified.]
4m = 4 + 4n [Equation 2]
Step 3: –4m + 4m = –32 – 8n + 4n [Equations in Step 2 are added.]
Step 4: 0 = –32 – 4n
Step 5: n = –8


In which step did the student first make an error?


Step 1
Step 2
Step 3
Step 4