Solve 2x2 + 5x + 5 = 0. Round solutions to the nearest hundredth.

No real solutions
x ≈ -3.27 and x ≈ 0.77
x ≈ -2.98 and x ≈ -7.02
x ≈ -0.77 and x ≈ 3.27

Question

Solve 2x2 + 5x + 5 = 0. Round solutions to the nearest hundredth.

 No real solutions
 x ≈ -3.27 and x ≈ 0.77
 x ≈ -2.98 and x ≈ -7.02
 x ≈ -0.77 and x ≈ 3.27

brunsonni · Answer

2x2 is 2x^2

campbell_st · Answer

you can use the determinant... to check the solutions 

or use the general quadratic formula to solve this

brunsonni · Answer

so a=2, b=5, and c=5, yeah?

brunsonni · Answer

@campbell_st  is it A, because i got x=-0.43, and x=-2.07 and those arent options.

campbell_st · Answer

well you shouldn't have been able to get answers... 

as 

the discriminant in this question is 

$$b^2 - 4ac = 5^2 - 4 \times 2 \times 5 = -15$$

and you can't take the square root of a negative number... 

so you choice of A is correct.

but your method is flawed

brunsonni · Answer

thanks