A woman looks out a window of a building. She is 94 feet above the ground. Her line of sight makes an angle of O with the building. The distance in feet of an object from the woman is modeled by the function d = 94 sec θ. How far are objects sighted at 25° and 55°?

Question

jim_thompson5910 · Answer

They want you to plug in 25 to get some number out for d. Same for 55

keep in mind that sec(theta) = 1/cos(theta)

jim_thompson5910 · Answer

http://web2.0calc.com/#94*(1/cos(25)) when you get to that link, hit the "=" button to have the calculator compute the result

haleyelizabeth2017 · Answer

I got that, but when I put it into my calc, it gives me answers wayyy off.  They are supposed to be something like 104 and 164 feet....I got 94.8366 and 4247.86 :(

jim_thompson5910 · Answer

make sure you are in degree mode

haleyelizabeth2017 · Answer

Desmos just sucks for sin/cos/tan lol

jim_thompson5910 · Answer

yeah I get 94*(1/cos(25)) = 94.8342749586472074 when I convert to radian mode

haleyelizabeth2017 · Answer

I'm not sure how to change it on there :(

jim_thompson5910 · Answer

click the wrench on desmos, and click "degrees" to convert to degree mode

haleyelizabeth2017 · Answer

Figured it out!  xD

haleyelizabeth2017 · Answer

lol....after you tell me :P  didn't notice you replied

haleyelizabeth2017 · Answer

Thank you!  Would you mind helping me with one more?

jim_thompson5910 · Answer

sure

haleyelizabeth2017 · Answer

Okay! Thanks!  Lemme find it real quick lol

jim_thompson5910 · Answer

ok