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algebra!
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@pooja195
not sure @rvc
@Michele_Laino help please!
hey what is 2x+4x=?
correct! here you take x as the variable and keep it aside and add the numbers Similarily with the roots since both are cube roots so multiply them
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we can write this: \[\Large \sqrt[3]{9} \times \sqrt[3]{{15}} = \sqrt[3]{{15 \times 9}}\]
\[\huge \sqrt[n]{b}.\sqrt[n]{a}=\sqrt[n]{ba}\]
here n=3 b=9 a=15
that's right! @wade123
:)
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