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Use the discriminant to determine the number and type of solutions the equation has. x2 + 6x + 12 = 0 A. one real solution B. two rational solutions C. no real solution D. two irrational solutions
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x=(-b+- sqrt(b^2-4ac)/2a
aX^2+bx+c=0
so im thinking b or d
im not sure tho!:D
a=1 b=6 c=12
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(-6+-sqrt(36-4*12*1)/2 (-6+-sqrt(36-48)/2
(-6+-sqrt(-12)/2 no real sol
okay!
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