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Mathematics 12 Online
OpenStudy (anonymous):

Use the discriminant to determine the number and type of solutions the equation has. x2 + 6x + 12 = 0 A. one real solution B. two rational solutions C. no real solution D. two irrational solutions

OpenStudy (anonymous):

x=(-b+- sqrt(b^2-4ac)/2a

OpenStudy (anonymous):

aX^2+bx+c=0

OpenStudy (anonymous):

so im thinking b or d

OpenStudy (anonymous):

im not sure tho!:D

OpenStudy (anonymous):

a=1 b=6 c=12

OpenStudy (anonymous):

(-6+-sqrt(36-4*12*1)/2 (-6+-sqrt(36-48)/2

OpenStudy (anonymous):

(-6+-sqrt(-12)/2 no real sol

OpenStudy (anonymous):

okay!

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