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Mathematics 20 Online
OpenStudy (anonymous):

Find the area of a regular nonagon with an apothem 16.5 inches long and a side 19 inches long. [A] 1410.8 in2 [B] 171.0 in2 [C] 2821.5 in2 [D] 256.0 in2

OpenStudy (anonymous):

Is this the right formula A=9/\[9/4 a ^{2}(180º/9)

jimthompson5910 (jim_thompson5910):

You will have 9 triangles that all look like this |dw:1433031577045:dw| they will arrange to form a nonagon

jimthompson5910 (jim_thompson5910):

find the area of 1 triangle, then multiply that area by 9

OpenStudy (anonymous):

Oh ok

OpenStudy (anonymous):

And what formula would I use for that?

OpenStudy (anonymous):

A = 1/2 bh

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

oh ok! And 19 would be the base, while the 16.5 is the height, correct?

jimthompson5910 (jim_thompson5910):

correct, what area do you get?

OpenStudy (anonymous):

Um, the final answer would be A right? But the area I got was 156.75

OpenStudy (anonymous):

And then when I multiplied that by 9, I got 1210,75 which would round up to 1410.8

jimthompson5910 (jim_thompson5910):

very good, you nailed it

OpenStudy (anonymous):

Thank you!

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