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Graph the line with the slope 1/3 passing through the point( -2,5)
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y=mx+b?
Not thats slope intercept :3 \[\huge y-y1=m(x-x1)\]
\[\huge(x1,y1)\] \[\huge~m=slope\]
so m would be 1/3 and x1 y1 would be -2,5?
yep and now we plug it in :) \[\huge~y-5=\frac{ 1 }{ 3 }(x+2)\] two negatives make a postitve thats where the 2 came from :) can u solve this now?
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would the answer be m=1/3 and b= 17-3?
@pooja195
\[\huge y=\frac{ 1 }{ 3 }x+\frac{ 17 }{3 }\]
Now u just graph that
uhmm how exactly would I graph that
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Thank you so much :)
:)
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