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Mathematics
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DF bisects
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What do you know about segments EF and GF?
They're the same length?
Yes. Since they are the same length, you can set their expressions equal to each other and solve the equation for n.
Solve this equation for n. 2n - 6 = n + 5
n = 11?
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Yes. Now since n = 11, and FG = 2n - 6, plug in 11 for n in 2n - 6. What do you get?
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