Question

The function H(t)=-16t^2+vt+s shows the height H(t), in feet, of projectile launched vertically from s feet above the ground after t seconds. The initial speed is v feet per second.

Part A: The projectile was launched from a height of 82 feet with an initial velocity of 60 feet per second. Create an equation to find the time taken by the projectile to fall on the ground.

Part B: What is the maximum height that the projectile will reach? Part C: Another object moves in the air along the path of g(t)=10+63.8t where g(t) is the height, in feet, of the object from the ground at time t second

Answer 1

really need help;/

Answer 2

Ok, part A asked for an equaton, and i think it is 0=-16t^2 + 50t + 90?

Answer 3

nevermind. I wil ask later;/