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OpenStudy (anonymous):
A box contains 3 red and 7 green balls. You are going to choose 3 balls, 1 at a time, without replacement. Find the probability that you will choose 3 green balls. 7/24 21/30 42/720 343/1000
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OpenStudy (anonymous):
may I know how did you approached this question?
OpenStudy (anonymous):
This is one of my homework questions that I am stuck on.
OpenStudy (anonymous):
ok... you can choose 3 green balls from 7 green balls as 7C3 out of total balls 10C3 P= 7C3/10C3
OpenStudy (anonymous):
My book shows combinations in a different way, as C(3,7), is that the same as you are stating?
OpenStudy (anonymous):
Thank you!
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OpenStudy (anonymous):
yep.. welcome
OpenStudy (anonymous):
:)
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