Line NA is congruent to line PA, MO is perpendicular to NA, RO is perpendicular to PA, and MO=6 feet. and this is the shape http://assets.openstudy.com/updates/attachments/4fd03b3fe4b0e0466317e3ef-mskyeg-1339046737323-cusersmsgpicturesmc0064.jpg

Question

Line NA is congruent to line PA, MO is perpendicular to NA, RO is perpendicular to PA, and MO=6 feet.    and this is the shape http://assets.openstudy.com/updates/attachments/4fd03b3fe4b0e0466317e3ef-mskyeg-1339046737323-cusersmsgpicturesmc0064.jpg

anonymous · Answer

hey guys i rely need help on this. i'm out of options. please help

anonymous · Answer

Hmmm....This is hard

anonymous · Answer

No clue

anonymous · Answer

darn

anonymous · Answer

@igreen @paki

anonymous · Answer

What are you asked to solve for?

anonymous · Answer

po

anonymous · Answer

i don't think i can give you any solid geometric reasoning here... but I'm pretty sure PO = 3

you're given this..
|dw:1433140089676:dw|

anonymous · Answer

because A is the center of the circle, and AN is perpendicular to MO, it must bisect MO. therefore MN = NO
|dw:1433140254126:dw|

anonymous · Answer

you also know that AP and AN are equal lengths:
|dw:1433140308669:dw|

anonymous · Answer

oh my god thank you so much

anonymous · Answer

For the lines RO and MO to intersect at a point on the edge of the circle, and for both of the lines to be perpendicular to AP and AN respectively, OR has to be a reflection of MO
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