Question

Average an array)
Write two overloaded methods that return the average of an array with the following headers:
public static int average(int[] array)
public static double average(double[] array)
Write a test program that random generate ten integers between 0 – 100, and ten double values between 0 – 50. Invokes both methods, and displays all values and the average values. (All double numbers will be displayed with two-digit decimal places.)
as i have done somewhat but, still there is error in it. please solve this problem according to the question.

Answer 1

```
//generation
import java.util.Random;
Random rng = new Random(); //random number generator (int)
for(int i=0;i<10;i++)
array[i] = rng.nextInt(101); //nextInt(n) generates an int from 0...n-1
```
similarly use rng.nextDouble which generates a number from [0,1)

```
display(T arr) {
//loop over arr size
//print each element
}

avg(T arr) {
sum=0
loop over array
accumulate elements in arrayy and store in sum
divide by size of collection
}
```

Answer 2

I wrote the functions that you will need. The rest you can easily do.

https://gist.github.com/AlexeyNosych/cc23e780d58c5a67f279

Answer 3

Thanx for your kind help but m still confused... i did something which is as follows
ackage intdouble;

/**
*
* @author JAY
*/

import static java.lang.Math.random;
import java.util.Scanner;
import java.util.Random;
//import java.util.Random.nextint;


public class IntDouble {
public static int average(int[] array) {
int sum = 0;
int average = 0;
for (int i = 0; i < array.length; i++) {
random rn= new random();
sum += random.nextInt(100);
}
average = sum / array.length;
return average;

}

public static double average(double[] array) {
double sum = 0;
double average = 0;
for (int i = 0; i < 5; i++) {
sum += random.nextInt(50);
}
average = sum / array.length;
return average;
}

public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter Integer values: ");
int array1[] = new int[4];
for (int i = 0; i < array1.length; i++) {
array1[i] = input.nextInt();
}
int avg1 = average(array1);
System.out.println("Average of First Array: " + avg1);
System.out.println();

System.out.print("Enter Ten Double Values: ");
double array2[] = new double[10];
for (int i = 0; i < array1.length; i++) {
array2[i] = input.nextDouble();
}
double avg2 = average(array2);
System.out.println("Average of Second Array: " + avg2);

}
}

Answer 4

This is waht i did.. but it ask for number.. but i want to genrate the number randomly for both integer and double and and last it has to show those 10 random numbers..
Please complete this program... i am posting it again
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
package intdouble;

/**
*
* @author JAY
*/

import static java.lang.Math.random;
import java.util.Scanner;
import java.util.Random;
//import java.util.Random.nextint;


public class IntDouble {
public static int IntDouble(int[] array) {
int sum = 0;
int average = 0;



Random rn= new Random();
for (int i = 0; i < array.length; i++)
array[i] = rn.nextInt(101);

sum += Random.nextInt(100);

average = sum / array.length;
return average;

}

public static double IntDouble(double[] array) {
double sum = 0;
double average = 0;
{
Random rn= new Random();
for (int i = 0; i < 5; i++)
array[i] = rn.nextInt(101);
//sum += Random.nextInt(50);
}
average = sum / array.length;
return average;
}

public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter Integer values: ");
int array1[] = new int[10];
for (int i = 0; i < array1.length; i++) {
array1[i] = input.nextInt();
}
int avg1 = IntDouble(array1);
System.out.println("Average of First Array: " + avg1);
System.out.println();

System.out.print("Enter Ten Double Values: ");
double array2[] = new double[10];
for (int i = 0; i < array1.length; i++) {
array2[i] = input.nextDouble();
}
double avg2 = IntDouble(array2);
System.out.println("Average of Second Array: " + avg2);

}
}