Question

Simplify the trig expression.

Answer 1

\(\Large\frac{sin^2\theta}{1-\cos\theta}\)

Answer 2

\(\color{blueviolet}{\Huge\sf{sin^2\theta+cos^2 \theta\equiv 1}}\)

Answer 3

k?

Answer 4

yes. but that's not an option.

Answer 5

You are not allowed to use that ?

Answer 6

I'm confused. how do I use that?

Answer 7

http://prntscr.com/7bv1ju my choices

Answer 8

instead of \(\sin^2\theta\) what would you substitute?

Answer 9

1-cos^2? @amilapsn

Answer 10

\color{blueviolet}{\Huge\sf{Yes.}}

Answer 11

you forgot the `\(` and `\)`

Answer 12

then what do I do?

Answer 13

I did it intentionally... :D

Answer 14

okay XD

Answer 15

then use...

Answer 16

what's a and b?

Answer 17

\[\color{blueviolet}{\Huge\sf{a^2-b^2\equiv(a-b)(a+b)}}\]

Answer 18

just have a guess...

Answer 19

(I just asked you to factorize 1-cos^\theta)

Answer 20

right now I have 1-cos^2/1-cos (theta)

Answer 21

@amilapsn Can you still help? I'm confused

Answer 22

@amistre64

Answer 23

can you factorize \(1-\cos^2\theta\)?

Answer 24

how?

Answer 25

@amilapsn

Answer 26

you know this?

Answer 27

\color{blueviolet}{\Huge\sf{a^2-b^2=(a-b)(a+b)}}

Answer 28

not really

Answer 29

if you simplify the r.h.s. you'll get l.h.s. and you can prove it yourself....

Answer 30

rhs? lhs? what's that?

Answer 31

rhs = right hand side
lhs = left hand side

Answer 32

I still don't know how to do it

Answer 33

\[\color{blueviolet}{\Huge\sf{1-\cos^2\theta=(1-\cos\theta)(1+\cos\theta)}}\]

Answer 34

ok?

Answer 35

yes?

Answer 36

Now you have the answer

Answer 37

oh, so is the answer 1+cos theta?

Answer 38

yepp

Answer 39

\(\Huge\color{lime}{Thank~you!}\)

Answer 40

\[\color{blue}{\Huge\sf{You're ~Welcome!}}\]