Jorge's rectangular garden was 17 feet long and had a perimeter of 54 feet. He made his garden 5 feet longer. What is the area of his new garden?

Question

luigi0210 · Answer

If I remember correctly, the perimeter of a rectangle is $P=2l+2w$ and you have 17 ft for length. 

So you can solve it: $\large 54=2(17)+2w$ 

$54=34+2w$ 
$20=2w$ 
$10=w$ 

And the length got extended 5 more feet. 17+5=22

$\large A=l*w$ 

$\large A=22*10$ 

That should be it :)