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The two numbers rolled can be added to get a sum. Find P(sum is even). my answer is B check my work plz
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yes, half the numbers are even
Are talking about rolling two dice? If so, there are 36 sums as outcomes. 18 are even, and 18 are odd. \(P(even~sum) = \dfrac{number ~of~even~sums}{total~number~of~outcomes} = \dfrac{18}{36}\)
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