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If ƒ (x ) = 3x2 - x, find ƒ (-2).
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For example f(-3) = 3(-3)^2 - (-3) = 3(9) + 3 = 27 + 3 = 30
If ƒ (x ) = 1/3x2 - x, find ƒ (-2).
So in this case they're asking to plug in -2 for x because they're implying that x = -2.
@junae43, is it \[f(x) = \dfrac{1}{3x^2 - x}\] or \[f(x) = \dfrac{1}{3x^2} - x\]
thanks
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