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Mathematics 16 Online
OpenStudy (anonymous):

solve: 4/y+3 + 6/y-1=15/y^2+2y-3 I've gotten to here 4/y+3+6/y-1=15/(y+3)(y-1). I just don't know where I'm supposed to go from here.

OpenStudy (anonymous):

-5/6

OpenStudy (anonymous):

how do you get that though?

OpenStudy (anonymous):

@Rubyjadeluv

OpenStudy (anonymous):

@calmdownchar

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