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A bag has 2 green marbles, 3 red marbles, and 3 yellow marbles. What is the probability that you pick a green marble, do not replace it, and pick another green marble? A. 3/28 B. 1/28 C. 9/56 D. 1/8
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what is the probability you pick a green marble first?
2/8 or 1/4
ok good now that marble is gone what is the probability that the second one is green given that one green marble was chosen and not replaced?
1/7?
yes
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final answer you get via \[\frac{1}{4}\times \frac{1}{7}\]
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