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Mathematics 16 Online
OpenStudy (babynini):

Please check. The answer came out wrong o.0

OpenStudy (babynini):

OpenStudy (babynini):

@ganeshie8

OpenStudy (babynini):

is it y^2=25px ?

jimthompson5910 (jim_thompson5910):

square has an area of 25 ----> side length of the square is 5 units ----> focal distance is p = 5

OpenStudy (babynini):

ok. so what's the answer look like? o.o

jimthompson5910 (jim_thompson5910):

http://www.mathwords.com/f/focus_parabola.htm p > 0 since the parabola opens to the right p = 5 is the focal distance (h,k) = (0,0) is the vertex plug all that into 4p(x-h) = (y-k)^2

OpenStudy (babynini):

so plugging in the numbers it looks like 4(5)(xh)=(y-k)^2

jimthompson5910 (jim_thompson5910):

h = 0 and k = 0 too

OpenStudy (babynini):

4(5)(0-0)=(0-0)^2 erm then everything would equal zero :o

jimthompson5910 (jim_thompson5910):

x and y are left as they are

OpenStudy (babynini):

oh sorry hah

OpenStudy (babynini):

so it comes out to y^2=20x

jimthompson5910 (jim_thompson5910):

correct

OpenStudy (babynini):

yay!! :) thanks

jimthompson5910 (jim_thompson5910):

np

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