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Please check. The answer came out wrong o.0
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@ganeshie8
is it y^2=25px ?
square has an area of 25 ----> side length of the square is 5 units ----> focal distance is p = 5
ok. so what's the answer look like? o.o
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http://www.mathwords.com/f/focus_parabola.htm p > 0 since the parabola opens to the right p = 5 is the focal distance (h,k) = (0,0) is the vertex plug all that into 4p(x-h) = (y-k)^2
so plugging in the numbers it looks like 4(5)(xh)=(y-k)^2
h = 0 and k = 0 too
4(5)(0-0)=(0-0)^2 erm then everything would equal zero :o
x and y are left as they are
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oh sorry hah
so it comes out to y^2=20x
correct
yay!! :) thanks
np
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