Question

"Calculus Lec1" Find the area of triangle enclosed by the axes and tangent to y=1/xPlease explain how to get the y-intercept algebraically not by symmetry. x=2x0 part.

Answer 1

we have the equation y-y0 = {-1/(xo)^2} * x-xo
put x=0 for y intercept
to get y - yo = {-1/(xo)^2}* 0-xo
-> y-yo = -1/(xo)^2 * -xo
-> y - yo = 1/xo
-> y - yo = yo as [yo = 1/xo]
-> y = 2yo